- !/\D/.test(m[3]) && "n+" + m[3] || m[3]),
- first = (test[1] || 1) - 0, last = test[2] - 0;
-
+ !/\D/.test(m[3]) && "0n+" + m[3] || m[3]),
+ // calculate the numbers (first)n+(last) including if they are negative
+ first = (test[1] + (test[2] || 1)) - 0, last = test[3] - 0;
+
+ // loop through all the elements left in the jQuery object